Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > #include <stdio.h>int main(){ printf(&q...
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#include <stdio.h>
int main()
{
printf("%d", main);
return 0;
}
int main()
{
printf("%d", main);
return 0;
}
- a)Address of main function
- b)Compiler Error
- c)Runtime Error
- d)Some random value
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
#include <stdio.h>int main(){ printf("%d", main); ret...
Understanding the Code
The provided code snippet attempts to print the address of the `main` function.
c
#include
int main()
{
printf("%d", main);
return 0;
}
Key Elements of the Code
- Function Pointer: In C, the name of a function can be used as a pointer to that function. Here, `main` refers to the `main` function itself.
- Address Representation: When you print a function pointer using `%d`, you are essentially printing the memory address where the `main` function is located.
Why Option 'A' is Correct
- Function Address: The output of `printf("%d", main);` yields the address of the `main` function in memory. This is valid and conforms to C standards.
- No Compiler/Runtime Errors: The code does not contain syntax errors, nor does it invoke any runtime errors. It will execute successfully, printing the address of the `main` function.
Potential Output
- The printed output will be the hexadecimal address of the `main` function in memory, often represented as a decimal number when using `%d`.
Conclusion
The correct answer to the question is option 'A' - Address of main function because the program successfully compiles and runs, displaying the memory location of the `main` function without any errors.
The provided code snippet attempts to print the address of the `main` function.
c
#include
int main()
{
printf("%d", main);
return 0;
}
Key Elements of the Code
- Function Pointer: In C, the name of a function can be used as a pointer to that function. Here, `main` refers to the `main` function itself.
- Address Representation: When you print a function pointer using `%d`, you are essentially printing the memory address where the `main` function is located.
Why Option 'A' is Correct
- Function Address: The output of `printf("%d", main);` yields the address of the `main` function in memory. This is valid and conforms to C standards.
- No Compiler/Runtime Errors: The code does not contain syntax errors, nor does it invoke any runtime errors. It will execute successfully, printing the address of the `main` function.
Potential Output
- The printed output will be the hexadecimal address of the `main` function in memory, often represented as a decimal number when using `%d`.
Conclusion
The correct answer to the question is option 'A' - Address of main function because the program successfully compiles and runs, displaying the memory location of the `main` function without any errors.
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Community Answer
#include <stdio.h>int main(){ printf("%d", main); ret...
Name of the function is actually a pointer variable to the function and prints the address of the function. Symbol table is implemented like this.
struct
{
char *name;
int (*funcptr)();
}
symtab[] = {
"func", func,
"anotherfunc", anotherfunc,
};
{
char *name;
int (*funcptr)();
}
symtab[] = {
"func", func,
"anotherfunc", anotherfunc,
};
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#include <stdio.h>int main(){ printf("%d", main); return 0;}a)Address of main functionb)Compiler Errorc)Runtime Errord)Some random valueCorrect answer is option 'A'. Can you explain this answer?
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